9709/31/M/J/25q9 – Mark Scheme
The constant s is such that .
(a) Show that [5 marks]
(b) Verify by calculation that a lies between 2 and 2.1. [2 marks]
(c) Use an iterative formula based on the equation in part (a) to determine a correct to 2 decimal places. Give the result of each iteration to 4 decimal places. [3 marks]
9709/32/M/J/25q6 – Mark Scheme
(a) By sketching a suitable pair of graphs, show that the equation has only one root in the interval
[2 marks]
(b) Show by calculation that this root lies between 1 and 1.5 [2 marks]
(c) Use the iterative formula with an initial value of 1.03 to calculate the root correct to 2 decimal places. Give the result of each iteration to 4 decimal places. [3 marks]
9709/33/M/J/25q11 – Mark Scheme

The diagram shows the curve for
. The curve has a maximum point at M, where x = a.
(a) Show that tan 2a = -4a [4 marks]
(b) Show by calculation that 0.9 < a < 0.95 [2 marks]
(c) Show that if a sequence of values given by the iterative formula converges, then it converges to a. [2 marks]
(d) Use the iterative formula in part (c) to calculate a correct to 4 decimal places. Give the result of each iteration to 6 decimal places. [3 marks]